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The degree of dissociation is given by,α = Λm / λo
here, α is the degree of dissociation, Λm is the molar conductivity λo is the molar conductivity at
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Given,Charge on an alpha particle, q1 = q2 = +2e Distance between the particles, r = 3.2 x 10–15 mNow, using coulomb s law, we get For
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We have, 5x2 – 8x – 4= 5x2 – 10x + 2x – 4= 5x (x–2) + 2 (x – 2)= (5x + 2) (x – 2)So, the value of 5x2 – 8x – 4 is zero when 5x + 2 = 0 or
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We are given a convex mirror. Here, we have Object size, h = + 5 cm Object distance, u = -20 cmRadius of curvature, R = + 3.0 cm [R is +ve for a conve
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Advantage of a knock-out tournament:
The knock-out tournaments are less expensive because the team, which gets defeated, is eliminated from the competition.
The
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The gas exerts pressure on the walls of container because molecules of gas are in random motion and strike with the walls of container and hence exert the thru
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The pipeline has certain advantages over other modes of transport:
1. The pipelines can be laid over difficult terrain as well as under water.
2. Their operation and maintenance cost is lower.
3. It involves very low energy consumption.
4. It ensures steady and constant supply of liquid and gases to the places at long distances.

5. It minimises transhipment losses and delays.

6. The pressure of carrying mineral oil and natural gas by railways has been reduced by the use of pipeline transport.

Disadvantages :

1. It is very difficult to desert leakage.

2. Their over laid capa

Rate of reaction can be dxdt=-12d(NH3)dt=d(N2)dt=13dH2dt=k.k is rate constant and reaction is of zero order. Therefore, rate of reactiondxdt=dH2dt=2.5×
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2-bromo propane is treated with alc. KOH, it forms propene which on further reaction with hydrogen bromide in presence of peroxide forms 1-bromo propane.
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2N2O5 (g) →   4NO2 (g)  + O2 (g)Rate of reaction -12d[N2O5]dt = 14d[NO2]dt
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⇒ Sn – 1 = 5(n – 1)2 + 3(n – 1)∴ Sn – Sn – 1 = (5n2 + 3n) – [5(n – 1)2 + 3(n – 1)}⇒ an = (5n2 + 3n) – {5 (n2 – 2n + 1) + 3n
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(Get CBSE, ICSE and all State Boards textbook solutions for all subjects Class 8 to 12. You can also get CBSE solved papers of previous year from here! You can also prepare for SSC. Can also test SSC, find SSC Resource centre ! You can get resources online for free for NEET, NEET previous year solved paper and JEE, JEE Previous year solved papers! Student can also find the, previous year papers etc. This is an organizat